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The “jailbreak method” call be applied to any root. In other words it works for a cube root, fourth root, fifth root, or any root with some slight modifications.

Example 1 ( Each of these examples are worked out in the video)

Simplify ∛16

Step 1 Create a factor tree

Step 2 Now determine who gets to “jailbreak” because you are working with a cube you look for triplets of like prime numbers

In this example there is one triplet of 2’s so they escape and one 2 remains under the radical which equals 2√2

## How to Simplfy a Cube Root

Simplify ∜512

Step 1 Create a factor tree

Simplify ∜81

Step 1 Create a factor tree

Step 2 Now determine who “ jailbreaks” This time you are working with a fourth root so you look for 4 like prime numbers

Step 3 There is one group of 4 like prime numbers so they escape and you have none left over so you have an even forth root of 3.

Step 4 ∜81=3

Step 2 Two groups of four 2's escape and one two remains. Remember, the problem involves simplfying a fourth root so you are looking for groups of four prime numbers that are the same.

2*2∜4=4∜2